Contents

Introduction

  • University with 15,000 students
  • Let represent the number of courses a randomly selected student is registered for
    • The pmf (probability mass function) of is provided
      • Example:
        • Calculation:
          • 150 students are registered for one course
      • Similarly for other values:
        • gives the number of students registered for courses

(3.6)

1234567
.01.03.13.25.39.17.02
Number registered1504501950375058502550300

  • The average number of courses per student (average value of ) is calculated as:

    • Total number of courses taken by all students divided by the total number of students
  • Example breakdown: - 150 students taking 1 course contribute courses to the total - 450 students taking 2 courses contribute courses to the total - And so on for other groups of students

    • The population average value of is given by: \frac{1(150) + 2(450) + 3(1950) + \cdots + 7(300)}{15,000} = 4.57 \tag{3.7}
  • Alternative expression:

    • Since:
      • And similarly for other values
    • The population average value of can also be expressed as: 1 \cdot p(1) + 2 \cdot p(2) + \cdots + 7 \cdot p(7) \tag{3.8}
    • This alternative expression shows that the average value of is a weighted sum of the number of courses, weighted by their probabilities.
  • Expression (3.8) shows:

    • To compute the population average value of , we only need:
      • The possible values of
      • Their corresponding probabilities (proportions)
    • The population size is irrelevant as long as the pmf is given by (3.6)
  • The average or mean value of :

    • Is a weighted average of the possible values
    • The weights are the probabilities of those values
    • For example, , , …,
  • This simplifies the computation since the exact number of students isn’t necessary;

    • we just need the distribution of the number of courses each student takes.